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manual:chapter3:symbolic [2018/12/14 11:42]
claudio [Algebraic Rules] |
manual:chapter3:symbolic [2018/12/14 11:49]
claudio [Algebraic Rules] |
| | ''%%'%%.NN*.vX^2:->.NN*(.vX-1)^2%%'%%'' | ''%%'%%√3*(X-1)^2+2.5*X+5*X*Y+(A+B)*Y^2%%'%%'' | Using ''.NN'' instead, matches ''√3'' and does the replacement | | | ''%%'%%.NN*.vX^2:->.NN*(.vX-1)^2%%'%%'' | ''%%'%%√3*(X-1)^2+2.5*X+5*X*Y+(A+B)*Y^2%%'%%'' | Using ''.NN'' instead, matches ''√3'' and does the replacement | |
| | ''%%'%%.xN*.vX^2:->.xN*(.vX-1)^2%%'%%'' | ''%%'%%√3*(X-1)^2+2.5*X+5*X*Y+(A+B)*(Y-1)^2%%'%%'' | Using ''.xN'' instead, matches ''√3'' and ''(A+B)'' as well | | | ''%%'%%.xN*.vX^2:->.xN*(.vX-1)^2%%'%%'' | ''%%'%%√3*(X-1)^2+2.5*X+5*X*Y+(A+B)*(Y-1)^2%%'%%'' | Using ''.xN'' instead, matches ''√3'' and ''(A+B)'' as well | |
| | ''%%'%%.NN*.vX^2+.XR:->.XR%%'%%'' | ''%%'%%2.5*X+5*X*Y+(A+B)*Y^2%%'%%'' | Finds ''√3*X^2'+...'' where ''.XR'' represents the rest of the expression, and removes the term from the expression | | | ''%%'%%.NN*.vX^2+.XR:->.XR%%'%%'' | ''%%'%%2.5*X+5*X*Y+(A+B)*Y^2%%'%%'' | Finds ''√3*X^2'+...'' where ''.XR'' represents the rest of the expression, and removes the term | |
| | ''%%'%%.xN*.vX^2+.XR:->.XR%%'%%'' | ''%%'%%2.5*X+5*X*Y%%'%%'' | Finds ''√3*X^2'+...'' and removes the term from the expression, then also finds ''(A+B)*Y^2'' and removes it as well | | | ''%%'%%.xN*.vX^2+.XR:->.XR%%'%%'' | ''%%'%%2.5*X+5*X*Y%%'%%'' | Finds ''√3*X^2''' and removes the term, then also finds ''(A+B)*Y^2'' and removes it as well | |
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